The upper half of an inclined plane of inclination theta is perfectly

For first half acceleration = g sin theta Therefore, velocity after travelling ball distance v^(2) = 2(g sin theta)l For second half, acceleration = g(sin theta - mu(k) cos theta) so 0^(2) = v^(2) = 2g (sin phi - mu(k) cos phi)l Solving (i) and (ii) we get mu(k) = 2 tan theta

22. The wor ld clined plane of inclinatione Dettedy s o white bower bahis rough. A Starting tones the of the pane will Begann come to cost the bottom the outcoment Auction

The upper half of an inclined plane of inclination `45^(@)` is perfectly smooth while

59. The upper half of an inclined plane of; of inclination rough. A block will again come f friction between smooth while the lower half rough starting from rest the of the

The upper half of an inclined plane with inclination $\phi $ is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to

If A body is released from the top of an inclined plane of inclination theta. It reaches the bottom with velocity V. If keeping the length same the angle of the inclination

The upper half of an inclined plane with inclination phi is perfectly

The upper half of an inclined plane of inclination θ is perfectly smooth while lower half is rough. A block starting from rest at the top of the plane will again come

Solved] The upper half of an inclined plane of inclination θ is perfectl..

SOLVED: The upper half of an inclined plane with inclination ϕ is perfectly smooth, while the lower half is rough. A body starting from rest at the top will again come to

SOLVED: The upper portion of an inclined plane of inclination alpha is smooth and the lower portion is rough. A particle slides down from rest from the top and just comes to

c) 3 kg Y 5 is perfectly 0. The upper half of an inclined plane of inclination smooth while lower half is rough. A block starting from rest the of the plane